Tell the reason

Question

I am writing at the end of program..
Cout<< p;
Cout << &p;
It giving different memory address what does it mean ??

Answer 1

Assuming 'p' is some pointer, then
cout << p;
will give you the memory adress of the cell the pointer is currently pointing to, while
cout << &p;
will give you the memory adress of the pointer variable itself, since a pointer is also a variable that sits on the stack and therefore has a memory adress.

Answer 2

Thnx bro