Why my code print 0000000000 ?(sorry my bad english)

Question

j++ <=> i add 1, right ?

So i try, j=j++ in loop

For (int i=0; i<10; i++){
j=j++;
cout<<j;
} And it print 0000000000 not 123456789 ?

My code
https://code.sololearn.com/cT7o9x3KDyDE/?ref=app

Answer 1

Tài Nguyễn.G yes because in the sequence assignment the first value which is readed is j=0 and the post increment will assign the 0 value to j so this way every time printed value of j will be 0 so 10 times 0 will be printed.

You have to do like this.

#include <iostream>
using namespace std;

int main() {
int j=0;
for (int i=0; i<10; i++){
j++;
cout<<j<<endl;
}
return 0;
}

Answer 2

Take a look at

https://www.sololearn.com/Discuss/1271878/?ref=app

Answer 3

Tài Nguyễn.G
It is not specified when between sequence points modifications to the values of objects take effect in your assignment of J = j++ thats why the sequence error is giving warning ⚠.

So just replace that line with only
j++;

And rest of the code will work fine.

Answer 4

Here's the fixed version :

https://code.sololearn.com/c36kmm7AUNsy/?ref=app

Answer 5

This is the mistake :
j=j++;
It should be :
j=++j;
As you are using j++ which means post increment . j=j++; here means that first assignment will take place i,e j=0; then increment j's value . So when assignment will take place first then how could be j can incremented
So try to use j=++j;
Now j's value will be first incremented then the assignment will take place
Like from 0 to 1 then 1 to 2 .... thanks