What is missing in this code which causing error and how to resolve this error??

Question

#include <stdio.h>

int main() {
char arr[10];
arr="word";
printf("%s",arr);
return 0;
}

Answer 1

You can't assign a string literal to a char array that already exist.

Either you do it directly:

char arr[10]="word";

Or you use the strcmp function from string.h.

Or you do it by hand, letter by letter with a loop, writing a 0/'\0' at the end.

Answer 2

Either use char are[10]="xyz"
Or use strcpy(are[10], "xyx") with library of #include<string.h>

Answer 3

Actually when you are writing arr="word", its logically incorrect. Actually arr denotes the address of the first element of your array and it does not represent your array. So you should write char arr[10]= "word", thus initializing at the time of declaration. This will work. Kudos..