++ Operator

Question

int i=0,x;
x= ++i + ++i;
Why x is 4?

Answer 1

++i adds 1 before calculating.
++i = 1
remember that i is always the same variable!
since i no longer is 0, the second ++i = 1+1 = 2.
you might think it now looks like this:
1 + 2
but that is wrong. it is 2+2. the SAME variable. you just changed it twice. now its 4.

I think this is how it works :).

Answer 2

The answer is 4 in C++ but 3 in JavaScript.

In C++, both ++ are executed first. So, 'i' becomes 2 and 2+2 becomes 4.

In JavaScript, left to right evaluation is done. So, the result is 1+2 which is 3.

Answer 3

X equals to 2 not 4. Prefix(++x) proceeds to increment first and then with the expression. Postfix(x++) first evaluates and then the expression.

Answer 4

i tested it and got 4
#include<iostream>
using namespace std;
int main()
{
int i=0,x;
x = ++i + ++i;
cout<<x;
return 0;
}