Can someone please explain to me how this python code works. I found it in a challenge and I'm clearly missing something...

Question

>>>def func(num):
>>> g=lambda x:1 if x==1 else x*g(x-1)
>>> return g(num)
>>>print(func(4))

The output is: 24

Answer 1

It is a function to find factorial...

g = lambda x: 1 if x == 1 else x*g(x-1)

here func(4) is printed
Then num == 4
And in

return g(num)

We can see that x == num

So

g(4) willl be

4 * g(3) ...(i)

now again, we have to find g(3)

which is 3 * g(2)

So (i) can be written as

4 * 3 * g(2)

Similarly for g(2)

4 * 3 * 2 * g(1)

Now x == 1 so it will return 1

So it will be

4 * 3 * 2 * 1

Which is 24

You can learn about lambda here

https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2460/?ref=app