python program to replace the 2nd occurrence of all characters in a given string??

Question

def replace(e):
for i in range(0,len(e)-1):
if i==len(e)-1:
return e
else:
a=""
d=[]
for j in range(i+1,len(e)):
if e[i]==e[j]:
c=j
d=[e[k:k+c] for k in range(0,len(e),c)]
d[1]=d[1].replace(d[1][0],"

Answer 1

Do you want to replace the duplicated characters if they are consecutively or when the second character occurance is wherever it appears?

Answer 2

This is a generic code that replaces duplicated characters:

inp = list("restabcdefgrest")
res = []
for i in inp:
if i not in res:
res.append(i)
else: #(1)
res.append('#x27;) # (1)
print(''.join(res))

If you want to remove duplicated characters instead of replace them, you can remove the lines marked with #(1).

Answer 3

Thank you😊

Answer 4

Am just in sowing stage of python nd I didn't getting why this recursive code isn't working...

Answer 5

When the second character occurs