Can each list value divided by some number ?

Question

Want to add 3rd section in table with factor by 2nd section of data value
https://code.sololearn.com/cWFxhezLD1w1/?ref=app

Answer 1

ғᴜɴ 3x
Yes there is a way.

original = [1,2,3,4,5]
newlst = []
for i in original:
newlst.append(i/2) #i/anything
print(newlst)

another, shorter way.

a = [1,2,3,4,5]
c = [i/2 for i in a]
print(c)

Answer 2

Additionally we have the map function.
c = list(map(lambda x:x/2), a)

Answer 3

can u tell us more about the program?

Answer 4

maf not clear for me too.

Answer 5

strength = [i/22.5 for i in load]
Did u encounter a problem?

Answer 6

maf

It works but i shuffle that list so result is mixed up

https://ibb.co/v11t4nb

I want strenth by dividing value of load by 22.5

Answer 7

Oma Falk help him bro i can't solve the problem :D
Idk why the answer is different, sorry

Answer 8

Thank you both solved <3

I want another section for average the 3 values in strenth

Answer 9

ғᴜɴ 3x np.
This wouldn't be a list so,

avg = sum(strength) / len(strength)

Answer 10

maf letme try this

Answer 11

Oma Falk
I want to make a report card for personal use
Which have random values in each

Answer 12

+--------+------+--------------------+
| weight | load | strenth |
+--------+------+--------------------+
| 8.99 | 545 | 21.24444 |
| 8.66 | 485 | 21.288888 |
| 8.88 | 491 | 21.333332 |
+--------+------+--------------------+

Here i want 545/22.5 = strenth
24.22 not random amswer