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How to modify the program so that it does not repeat the pairs, without creating new array
# Print all pairs of numbers in array A whose sum is greater than 10 A = [4,5,2,1,3,7] for value_1 in A: for value_2 in A: total = value_1 + value_2 if (total > 10): print (value_1, " + ", value_2, " > 10") # OUTPUT # 4 + 7 > 10 # 5 + 7 > 10 # 7 + 4 > 10 <-- Repeated # 7 + 5 > 10 <-- Repeated # 7 + 7 > 10 <-- same element
4 Réponses
+ 8
This is the best solution I could think of:
def pair(li,n):
pairs = []
for i in li:
for j in li:
c = sorted((i,j))
total = i + j
if total > n:
if c not in pairs:
pairs.append(c)
yield c
A = [4,5,2,1,3,7]
for (x,y) in pair(A,10):
print(x,y)
#output: 4 7
#output: 5 7
#output: 7 7
I hope it helps :)
+ 7
@richard Great solution!
+ 2
test = [4,5,2,1,3,7]
for ind,item in enumerate(test,1):
indx = ind
while indx < len(test):
if item + test[indx] > 10:
print(item,test[indx])
indx +=1
# or you may want to research itertools
# for more wide ranging applications of list pairings
import itertools
for i in itertools.combinations(test,2):
if sum(i)>10:
print(i)
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Thank you very much Aidan, very good answer, but your code makes use of an array to save the pairs. I try to do it without that array.