Логический оператор OR

Question

Я думал что для выполнения логического оператора OR достаточно чтобы было True первое утверждение.
Но код который ниже проверяет две условия ( while цикл), т.е. проверяет значение первого и второго числа. Подскажите пожалуйста почему так?

Ask the user for two numbers between 1 and 100. Then count from the
lower number to the higher number. Print the results to the screen.
'''
num_1 = int(input('Please enter a number between 1-100:> '))
num_2 = int(input('Please enter a number between 1-100:> '))

while num_1 < 0 or num_2 < 0 or num_1 > 100 or num_2 > 100 or num_1 == num_2:
print('Numbers must be different values between 1 and 100, try again')
num_1 = int(input('Please enter a number between 1-100:> '))
num_2 = int(input('Please enter a number between 1-100:> '))

if num_1 < num_2:
for i in range(num_1,num_2+1):
print(i,end=' ')
else:
for i in range(num_2,num_1+1):
print(i,end=' ')

Answer 1

OR - if anyone condition evaluates to true the whole expression is True.
having a while loop and 1 condition True is a jackpot, as unless you enter correct values you are trapped in an infinite loop.

and if u wish to get to know which input is wrong, it would be better to multiple if conditions inside of the while loop like:-

while True:
if num_1 < 0 or num_1 > 100:
num_1 = int(input('Please enter a number between 1-100:> '))
elif num_2 < 0 or num_2 > 100:
num_2 = int(input('Please enter a number between 1-100:> '))
elif num_1 == num_2:
num_1 = int(input('Please enter a number between 1-100:> '))
num_2 = int(input('Please enter a number between 1-100:> '))

By this, your code would be a bit longer than excepted but it should do your work just fine.