I don't understand why can't initialize strings like this

Question

import java.util.ArrayList;
import java.util.Scanner;

public class Main {
public static void reapeat(int n,String...b)
{
//String b;
}

public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("enter the number of baloon");
Scanner sc=new Scanner(System.in);
int n= sc.nextInt();
ArrayList<String>colors=new ArrayList<String>();
// ArrayList<String>colors2=new ArrayList<String>();
System.out.println("enter the name of "+n+" color(s)");
String []s;
s=new String[n];
for(int i=0;i<=n;i++)
{

colors.add(sc.nextLine());
s[i]=colors.get(i);

}

}

}

Answer 1

David Bukedi Problem is your for loop. You are doing like this:-

for(int i=0;i<=n;i++)

Here suppose you are taking n = 5 but according to your loop it will go i = 0 to i = 5 which will give IndexOutofBound exception Because you have String Array with size 5 only. But you are accessing 6th value from the array.

s[o]
s[1]
s[2]
s[3]
s[4]
s[5] // Wrong, give IndexOutofBound exception

You need to change your loop by this:-

for(int i=0;i<n;i++)

Answer 2

Thank you

Answer 3

It's a problem with Sololearn input. We cannot take input inside loop. We have to take multiple input with new line.

https://code.sololearn.com/WhiNb9BkJUVC/?ref=app

Answer 4

Ho nonono don't pay attention to the function repeat, just the function main

Answer 5

That's where i get the index out of bounds exception

Answer 6

Actually , I'm trying to find a way to initialize an array of strings with a for loop

Answer 7

declaration:
String b;

initialization:
String b = "";

But I would not use b as variable name because you used already b as parameter (String...b).

Maybe it helps to explain what you are want to do.