\\java.lang.ArrayIndexOutOfBoundsException

Question

import java.util.Scanner;
public class pigLatin {
public static void main(String[ ] args){

Scanner input = new Scanner(System.in);
String text = input.nextLine();
StringBuilder s1 = new StringBuilder (text);
char[ ] c = new char[s1.length()];
s1.append(' '); c[0]= s1.charAt(0);
s1.deleteCharAt(0);

for( int i = 0; i<s1.length(); i++ ) {
if( s1.charAt(i) == ' ') {
for(int j = 1; j<s1.length(); j++) {
c[j] = s1.charAt(i+1);
s1.deleteCharAt(i+1);
s1.insert(i, c[i-1]);
s1.insert(i, "ay"); } } }

System.out.println(s1);
} }

The above code can run and get user input but it can't print output as expect because of the exception. I think it probably due to output's capacity is greater than the input 's length... I've scratch my mind for an hour then I still have no idea. Could someone help me out, please!!?
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Answer 1

RnT.Lee
By your approach,
Ex if input is
abcd efgh ijk
You are starting copying when if(s1.charAt(i)==' ')
by this starts at 'efgh' so you are missing 'abcd'.
And doing it until s.length() so upto end not next space.. So should be j<i.
And s1.charAt(i+1) when reaches end raises index out of exception. So make sure i+1 must less than s1.length. Next statement also...

Answer 2

you have two typos,
first loop you used comma instead of semicolon
for(int i =0, ) should be for(int i =0;)
then you use C[j] while the original is not capital c. happens because of autocorrect I guess.

Answer 3

Bahha🐧 I scanned this code from my laptop through an app on smartphone. :v It often occur typos as you see. But i tried the original code a lot of time, it still not work... :(((((

Answer 4

Jayakrishna🇮🇳 I'm done! Thanks for your recommendation. 😅 Is the following code okay!?
import java.util.Scanner;
import java.util.StringTokenizer;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String text = input.nextLine();

StringTokenizer s1 = new StringTokenizer(text);
StringTokenizer s2 = new StringTokenizer(text);
char [] c = new char[s2.countTokens()];
String [] S= new String[s2.countTokens()];
String [] S2= new String[s2.countTokens()];

int i = 0;
while(s1.hasMoreTokens()){
c[i]=s1.nextToken().charAt(0);
i++;}

int p = 0;
while(s2.hasMoreTokens()){
S[p]=s2.nextToken();
p++;}

String val1= " "; String val2= " ";
for(int j=0; j<S.length;j++){
val1 = S[j].substring(1);
val2 = val1.concat(Character.toString(c[j]));
S2[j]= val2.concat("ay");}
for(String t:S2){
System.out.print(t+" ");}

}

}

Answer 5

Working fine...