Output

Question

Why in the in the second time it’s just let me input the address number and n I know because nextInt() but how I can solve it??

do
{
String name;
System.out.print("Enter your name? ");
name=input.nextLine();

String address;
System.out.print("Enter your Address? ");
address=input.nextLine();

int number;
System.out.print("Enter your number phone? ");
number=input.nextInt();

System.out.println("The information; ");
System.out.println(" your name? "+name);
System.out.println(" your address? "+address);
System.out.println(" your number phone? "+number);
System.out.println("if you want to enter again the information, enter y ");
again=input.next().charAt(0);
}
while (Character.toUpperCase(again)=='Y');

Answer 1

Reema , the Scanner.next method does not read the newline character created by hitting "Enter," so you might put input.nextLine() after

again =input.next().charAt(0);
input.nextLine();

to 'consume' the rest of the line and the newline character.
else, it will be 'consumed' by your

name=input.nextLine();

(which will be skipped)