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Can anyone please explain the answer of the below mentioned question?

#include<stdio.h> #define square(x) x*x int main() { printf("%d", square (4-1)); return 0; } The answer mentioned was -1

11th Apr 2020, 7:18 PM
VIKRANT
VIKRANT - avatar
2 Réponses
+ 1
#define is a macro, it will just replace square(expression) by expression*expression. so x=square(4-1)= 4 - 1*4 - 1= 4 - 4 - 1 = -1 if you want it to really calculate the square, use: #define square(x) (x)*(x) look here https://www.sololearn.com/Discuss/2233917/?ref=app
11th Apr 2020, 7:31 PM
John Robotane
John Robotane - avatar
+ 1
in your printf function...the square(4-1) is replaced with 4-1 * 4-1...so 4 - 1 * 4 - 1... 4 (-1 * 4) - 1.. 4 - 4 - 1... result = -1
11th Apr 2020, 7:36 PM
rodwynnejones
rodwynnejones - avatar