if statement

Question

What is the output of this code?
num = 7
if num > 3:
print("3")
if num < 5:
print("5")
if num ==7:
print("7")
sir, why the answer wont be 7?

Answer 1

Because 7 is not less than 5. So it will not go inside nested if part

Answer 2

Because the number isn't smaller than 5 only the first if statement will be executed.
The output will be 3.

Answer 3

I guess what you wanted to do is:

num = 7
if num > 3:
print(3)
if num < 5:
print(5)
if num == 7:
print(7)

Answer 4

This exact question was asked a week ago.
Read through this post for the answer in full

https://www.sololearn.com/Discuss/2232416/?ref=app

Answer 5

it's matter of blocks

if num >3: # True
print("3") # 3 printed

if num < 5: # False
print("5")

# here python go out of this block and don't excute any thing inside this block
# notice that if num == 7 is inside the False block.
that mean python will not print 5 and will not verify if num == 7
finally don't print 7

Answer 6

Because of the indentation, the code stop running after completing the first query.
if num >3: #True
print('3') #3

If you were to remove the indentation, then the code will examine each query for a result of 3
7

Answer 7

Thank you everyone for your clarification

Answer 8

This question is similar PRIYANKA K.
It won't print 7 because the second statement is false therefore leaving the third statement void.

Answer 9

the third if statement actullary has == not ==. so it will be if num === 7. I think

Answer 10

as num=7, so num<5 won't hold and only the first segment of the code will be executed.