Why this algorithm returns no output? Please help.

Question

# Expected output: 'tuxtax! tuxtax!' for False

def echo_sabre(func, x, y):
return func(func(x, y), func(x, y))

a = 'tux'
b = 'tax'

def merge(x, y):
return x + y

def maruhacho():
while False:
print (echo_sabre(merge, a, b, "!"))

if True:
print ("Qui, qui, je vois")

else:
maruhacho()

1==2

Answer 1

Because of the condition:

while False: is always fixed

2nd thing you have defined function with 3 parameters and while calling in another function you have passed 4 parameters.

3rd thing what is 1== 2 in your code.

Answer 2

First of all, you do not call any function. Second in maruhacho the while loop will never run, because you have a fixed False conditon. It will also always print "Qui, qui, je vois" as there is a fixed True.

Answer 3

Here one implementation using three arguments, so similar to the original one and one example using a tuple as input (*args), so that you are flexible in the amount of strings to concatenate.

https://code.sololearn.com/cDj3i2UNY1M5/?ref=app
https://code.sololearn.com/cX52cwHGMfK9/?ref=app

Answer 4

I don't think this can work, echo_sabre takes 3 arguments but you give it 4.

`echo_sabre(merge, a, b)` will give you "tuxtaxtuxtax". We can substitute in our heads to see:

def echo_sabre(merge, "tux", "tax"):
return merge(merge("tux", "tax"), merge("tux", "tax"))

You could `echo_sabre(merge, a, merge(b, "! "))` to get the expected result, or something very close anyway.

Answer 5

Manu_1-9-8-5 AJ #Infinity Love Hello and thank you! So, I attempted to call the maruhacho function by checking 1==2 statement.

How do I call it correctly to get the “tuxtax tuxtax” result?

Answer 6

Manu_1-9-8-5 Thank you, mate! Really appreciate your input!