XML Python

Question

Hello, I need to know how to get an attribute of an xml child node with python.
The xml looks something like this:

<?xml version="1.0"?>
<Transactions xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Transaction>
<GeneralData Ref="PX00103622" Type="AutofacturaComercial" Date="2020-02-20" Currency="EUR" BeginDate="2020-02-20" EndDate="2020-02-20" DeliveryAddrID="0" TaxIncluded="false" OnlyArchive="false"
<DigitallyCertified>true</DigitallyCertified>
</GeneralData>
<Reference DNRef="14273107/14273106" PORef="6500009101" InvoiceRef="20NV022515" DNRefDate="2020-02-26" PORefDate="2020-02-11" InvoiceRefDate="2020-02-20" />
</References>
.
.
.
.
</Transaction>
</Transactions>

You would need to get the data associated with Ref, Date and PORef; but I can't get it out

Answer 1

Check the xml module in python

'''
data associated with Ref, Date and PORef;

ATTENTION!!
https://docs.python.org/3/library/xml.etree.elementtree.html#xml.etree.ElementTree.Element.iter
'''
import xml.etree.ElementTree as ET

tree = ET.parse('example.xml')
root = tree.getroot()

attributes = []
search_attributes = ('Ref', 'Date', 'PORef')
for elem in root:
for _elem in elem:
attributes.append(_elem.attrib)

for i in attributes:
for k, v in i.items():
if k in search_attributes:
print(f'{k}:{v}')

Answer 2

I hope it will help you