I enter numbers in the console, press Enter, and it closes immediately

Question

#include <iostream>
#include <string>
#include <conio.h>

using namespace std;

int main()
{
int number;
cout << "Enter a number: ";
cin >> number; cout << endl;
if (number > 0)
{
cout << "1";
}
else if (number == 0)
{
cout << "0";
}
else if (number < 0)
{
cout << "-1";
}
getch();
return 0;

}

Answer 1

Yes I have done the same thing

Answer 2

Namit Jain (if else) is very much supported feature in C++. 👇

https://code.sololearn.com/cK46a8054SDU/?ref=app

And Sin Cara M as far as problem is conserned in your code then it is nothing just that you are using outdated C++ headers(conio.h) which is no longer a standard header.

Here is the fix of your code👇

https://code.sololearn.com/cz9PM5k9Nw0L/?ref=app

Answer 3

Namit Jain And how to do it?

Answer 4

https://code.sololearn.com/cu31FzsdphGH/?ref=app

Answer 5

Ohhhkk thanks Arsenic for the important info👍👍

Answer 6

Namit Jain Anything greater than 0 should be displayed "1", anything less than 0 is displayed "-1", if 0 then "0"

Answer 7

Arsenic Thank you very much, it works☺️

Answer 8

Everything is great, thank you ~ swim ~

Answer 9

Namit Jain I see, thank you very much)

Answer 10

Yes, everything is as you say) ~ swim ~

Answer 11

Sin Cara M You're Welcome😅

Answer 12

#include <stdio.h>

int main() {

int i;
while(scanf("%d",&i)>0)
{
if(i==0)
break;
}
printf("%d",i);

return 0;
}

Answer 13

I do not understand why, but it closes in me as soon as I enter the number, and wrote everything as Arsenic , ~ swim ~

Answer 14

I don't think 'else if' is anything in C++

C++ has only if and else

C has if/else if/else

So according to me you will have to make nested conditions to make it work correctly...