Area of triangle is ZERO! (This is a question from challenge). The output is different in both cases below. What's the reason?TY

Question

//CASE - 1
#include <iostream>
using namespace std;

int main()
{
float area, base = 5, height = 10;
area = (1/2)*base*height;
cout<< area;
return 0;
}

// Output = 0

// CASE - 2
#include <iostream>
using namespace std;

int main()
{
float area, base = 5, height = 10;
area = (0.5)*base*height;
cout<< area;
return 0;
}

// Output = 25

Answer 1

In the first case, (1/2) is treated as integer division, with 0.5 getting truncated to 0, which in turn turns the entire product into zero. Writing 1 as 1.0 would easily solve that problem.

Answer 2

Stellar Fox , ~ swim ~
I was thinking like this ↓
(1/2) = 0.5 it's a double so it will be used in operation without removing "5".
But I get it now. An integral fraction will not be treated the same as a float type fractional value.
(And being in the middle of a calculation won't save those integer numbers from being attacked by double! 😈)

Thank you two!