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whats the problem? and how can i make it with a while loop so it will run till the input is "exit"?

my_List = ["apple" , "orange" , "watermellon"] my_Input = input("what fruit do you want?\n") if 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 in my_Input: print("you can only write fruits! not Integers!") exit() else: if my_Input in my_List: print("we have " + my_Input) else: print("we dont have " + my_Input)

4th Jul 2020, 1:16 PM
Yahel
Yahel - avatar
3 Réponses
+ 1
thanks!
4th Jul 2020, 2:41 PM
Yahel
Yahel - avatar
0
Using exception handling block for reading input, my_List = ["apple" , "orange" , "watermellon"] digits = "1234567890" while True: try: my_Input = input("what fruit do you want?:") except EOFError: exit() if my_Input == "exit": exit() print(my_Input) for digit in digits: if digit in my_Input: print("you can only write fruits! not Integers!") exit() if my_Input.lower() in my_List: print("we have " + my_Input) else: print("we dont have " + my_Input)
4th Jul 2020, 2:06 PM
Ipang
0
Could you please check whether that code is what you expect! -------------------------------------------------------- my_List = ["apple" , "orange" , "watermellon"] my_Input = input("what fruit do you want?\n") while my_Input not in my_List: if my_Input.isalpha(): print("we don't have " + my_Input) elif isinstance(my_Input, int): print("you can only write fruits! not Integers!") my_Input = input("what fruit do you want?\n") print("we have " + my_Input)
4th Jul 2020, 4:33 PM
yyy