if x=5 then --x; y=--x; x=4 and y=4 but x--; y=x--; x=4 and y=5 right or wrong?

Question

This is true or false

Answer 1

the First one results in x and y = 3.
because you have x=5,
--x == predecrement x-1=4
y=--x == predecrement x-1=3 and store in y
print x and y

2nd ends with x=3 and y=4
again x=5
x--== postdecrement x-1=4
y=x-- == y gets the value of x and x is postdecrement after that so that y stores 4 and not 3, what x will be after finish this line.
print x=3 and y=4

Answer 2

You should get a compile error when you run this

Answer 3

actually, first, when you used x++ or ++x, then answer is always "x increase by 1".. eg;
if x=2, then x++ or
++x=1+x
=2+1
=3
or
x++=x+1
=1+2
=3
both, ++x and x++ are equal...

Answer 4

now see what I do...
suppose
y=++x, and =7;
here you see the table

phrases|int val of x|val of y|fnl val of x

y=++x. x=5. 6. 6

y=x++. x=5. 5. 6

y=--x. x=5. 4. 4

y=x-- x=5. 5. 4

here int val means initial value of x, value of y and final value of x