Arrays in loop and calculation

Question

How should one interpret the line a[0] /= a[x]; in the following code?

int main()
{
int a[3] = {9,4,2};

for(int x=1; x<2; x++) {
a[0] /= a[x];
}
cout << a[0];

From my understanding, a[0] is 9, the first element of the array.
Is it correct that a[0] /= a[x] is the same as a[0] = a[0]/a[x]?
What does the x in the square brackets of a[x] signify? --> I think this changes from 1 to 2 after the loop.
The final output is 2... Totally confused.

Answer 1

the loop is run only once.
so a[0] /= a[i] is a[0] = 9 / 4 == 2

Answer 2

Solus
If <i> in `a[0] /= a[i];` was mistaken for <x> (read: a typo), then I agree with Abhay and Bahha.

Otherwise, I don't see the declaration/definition of variable <i> : )

Answer 3

Ipang right, I didn't pay attention to " i ", brain autocomplete :) . by a[i] I meant a[x].

Answer 4

a[0]=a[0]/a[9]
a[0]=9/4
a[0]=2

Answer 5

Bahha🐧
Yup, I also was wondering where <i> came from 😁