+ 1
ID of unassigned list value
I see in python that ID of unassigned list value is always the same. For example id([1]) and id([1,2]) is same. How does it define this value and where I can read about such behavior?
2 Réponses
+ 4
It doesn't matter if you assign a list somewhere or not.
As soon as you write a list literal, the list will be created.
That means, Python will take memory for that and give an id.
The only difference is that the object will be garbage-collected after the statement is over, if you don't put a reference to it.
So list is created...
... destroyed...
... and the now free id is given to the new list.
At least that's what I'd suspect.
Try this:
print(id([]))
# a = []
print(id([]))
Id is the same.
Now if you uncomment line 2, the id differs.
+ 2
Its a ways down there but there's a lot of good information here on the whole
https://towardsdatascience.com/JUMP_LINK__&&__python__&&__JUMP_LINK-variable-assignment-9f43aed91bff