How can I make the binary array to be zeroes in the middle ?

Question

example
1 1 1 1 1
1 1 0 1 1
1 000 1
1 1 0 1 1
1 1 1 1 1
// my code
CODE
#include <iostream>
using namespace std;
void generaMB1(int n, int m[][25]){
int f,c;
for(f=0;f<n;f++){
for(c=0;c<n;c++){
if((f+c)==3 || (f+c)==4 || (f+c)==5 && f!=1 && c!=1 && f!=0 && f!=4 ){
m[f][c]=0;
}else{
m[f][c]=1;
}
}
}
}
void listaMatriz(int n, int m[][25]){
cout << endl << "LISTADO DE LA MATRIZ"<<endl;
for(int f=0;f<n;f++){
for(int c=0;c<n;c++){
cout <<" "<<m[f][c];
}
cout << endl;
}
}
int main(int argc, char *argv[]) {
int m[25][25];
int n=5;
generaMB1(n, m);
listaMatriz(n, m);
return 0;
}

Answer 1

you could always hard code it.....
int x = [
[1 1 1 1 1]
[1 1 0 1 1]
[1 0 0 0 1]
[1 1 0 1 1]
[1 1 1 1 1]];
//missing commas... not syntactically correct :/

Answer 2

maybe:
int mid = n/2;
if ((f == mid && c!=0 && c!=n-1) || (c == mid && f!=0 && f!=n-1))
{m[f][c] = 0}
else
{m[f][c]=1}