help!!!!

Question

int main(){

string names[4]={"ddd","fff","bbb","xxx"};

//does not work
for( string&& i :names){
cout <<i <<endl;
}
//does not work
for(const auto&& i :names){
cout <<i <<endl;
}
//it works i meant auto&& and string&& are same thing here ,don't they?the damn part is what is wrong with const auto&&
for( auto&& i :names){
cout <<i <<endl;
}
}

Answer 1

so...? what is your question?

Answer 2

No, string&& and auto&& are not the same thing.
string&& is trying to declare a rvalue reference as a lvalue.
With auto&& auto will decide the type, this is really the same as const auto&

This may help.
http://stackoverflow.com/questions/5481539/what-does-t-double-ampersand-mean-in-c11

valid signatures are:
for (string i: names)

for (string& i: names)

and:

int main(){

string names[4]={"ddd","fff","bbb","xxx"};

for(const string& i :names){
cout <<i <<endl;
}

for(const auto& i :names){
cout <<i <<endl;
}

for( auto&& i :names){
cout <<i <<endl;
}

return 0;
}

Answer 3

The question is why auto&& works but string&& ,const auto&& dont?

Answer 4

ok thank you guys but the point I get from all your answer is const can change lvalue reference to accept rvalue,
the new question is, how this work? a quick description will be very useful