Why this code make this output? ( It ouputs [I@xxxxxxxx ) without any errors

Question

Code:

public class Main {

public static void main(String[] args) {
int[] map = {1, 1, 1, 1, 1,
1, 1, 1, 1, 1,
1, 1, 1, 1, 1,
1, 1, 1, 1, 1,
1, 1, 1, 1, 1};

System.out.println(map);
}
}

I am using another compiler, not sololearn's playground

Answer 1

You are printing the memory address of the array and it will give you the same result everytime you run it.

You can use the Arrays class and call the toString method and pass your array (map) as parameter:

System.out.println( Arrays.toString(map) );

You can also use an for-each loop if you want:

for(int elemens: map)
System.out.println(elemens);

Answer 2

I think it outputs the adress of the map?
Well map is defined as int[]
means map points to the computer adress of the first 1
Try to print map[0] to accesss first element

More to arrays in Java:
https://www.sololearn.com/learn/Java/2148/

Answer 3

The output is random every time

Answer 4

Try this:
System.out.println(map.toString);
At the last!

And I hope you know that you have made a uni dimensional array

Answer 5

Thanks For all answers!

Answer 6

you are welcome