If condition in Python not working as expected?

Question

The if condition doesn't work for two arguments i.e. quit or exit
The problematic code is placed after the user input ( variable answer )

import random
cond = True

while cond:
choiceList = ["rock", "paper", "scissors"]
guess = random.choice(choiceList)
score = 0
computer = 0

# asking input for the guess
answer = input("\nYou choose: ")

""" This doen't work for both conditions quit or exit """
""" More specifically it doesn't take two arguements """
""" quit as well as exit, but works completely fine for either one """

if(answer != "quit" or answer != "exit"):
print("Computer choose: " + guess)

if(answer == "quit" or answer == "exit"):
cond = False
else:
print("Please input correct option!")

Answer 1

Your first if statement will always evaluate true...

Answer 2

yes as Arnesh said, theres no false in that statement

maybe try use 'and' instead of 'or'

Answer 3

Why are you checking condition - "if input is not "quit or "exit" If you wrote condition below - "if input is quit or exit, break loop"
This makes no sense, maybe you wanted to show computer choice ONLY if user input ISN'T exit or quit.

But at Sololearn codeplayground it also makes no sense, because user makes input only once..

And it would be more appropriate if you replace "while" loop with simple if.