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Generate random number then make triangle pattern in python.

How can I generate a random number between 5 and 10 then print that random number and make a triangle pattern counting down to 1 on each line. Example: The random number generated is 5 5 4 3 2 1 4 3 2 1 3 2 1 2 1 1

5th Mar 2017, 10:47 AM
Bn H
Bn H - avatar
2 Réponses
+ 1
Thanks for the answers,was looking for this : def inverted_tree(length): for length_2 in range(length, 0, -1): for k in range(length_2, 0, -1): print(k, end=' ') print() return '' from random import choice k = choice(range(5,10)) print("The random number generated is",k) print(inverted_tree(k))
5th Mar 2017, 11:43 AM
Bn H
Bn H - avatar
- 1
I don't know python but i can tell you how is it going to be done in java(Logic is same). 1:Use random method from "math" class. 2:Give that number into a method that does the work of creating triangle like following(Compiled and runnable): public void generateTriangle(int random_number){ for(int i=random_number;i>=1;i--){ for(int k=i;k>=1;k--){ System.out.print(k+" "); } System.out.println(""); } } 3:Call the "generateTriangle" method and ...Ta..Da :P By the way i don't like pattern challenges because they are all done using "nested loops" and its kinda useless in my opinion for any real world task.
5th Mar 2017, 11:43 AM
Fahad
Fahad - avatar