+ 1
can anyone help me to Slove this please?
https://www.sololearn.com/coach/73?ref=app import math as m word=str(input()) a=word.split() n =0 b=list(a) d=len(b) for i in b: n+=len(i) n=n/d print(m.ceil(n))
3 Réponses
+ 7
Strange , befor asking for help, you are requested to present your attempt first. Please put it in playground and link it here. Thanks!
+ 2
phrase = input("")
words=0
letters = 0
for i in phrase:
if i == ' ':
words+=1
elif i != '?' and i != ' ':
letters+=1
words += 1
avg = letters/words
avg2 = int(avg)
if avg2 < avg:
avg2+=1
print(avg2)
+ 2
I don't know if it's the most efficient solution but here is how I would have solved this problem.
# inputing the string
string = input()
# importing ceil function from math module to round up to the nearest whole number
from math import ceil
# the number of words is the length of the list generated when the string is split by spaces
words = len(string.split())
# setting letters to zero
letters = 0
# getting each character in the string
for char in string:
# checking if it is an alphabet
if char.isalpha():
# incrementing letters by 1
letters += 1
# the average is the number of letters divided by the total number of words
average = letters / words
# printing the average rounded up to the nearest whole number
print(ceil(average))