C language ; operator working princible

Question

I realized that C compliers doesnt give errors when only put ; repeatly. I mean ; is used to execute a task. But when no task is given what does it execute ? I am leaving an example.
#include <stdio.h>

int main()
{
;
;
;
return 0;
}

Answer 1

its like its executing nothing over and over again, then returns 0

Answer 2

Slick we have NOP() to execute nothing. NOP stands for no operation

Answer 3

Right, but there is literally nothing for gcc to compile. So technically it would have no errors. Thats the only thing i can think.

like in a for loop AFTER you have assigned an int variable.

...
int i=0

for(;i<5;i++)
...

The assignment is skipped but it still runs fine because there are technically no errors.

Answer 4

Slick hımm kinda make sense. Still one thing is not clear, it is not valid in while loop.
If no input is given to while loop it throws an error. You can try.
while()
{
printf("hello world\n");
}

Answer 5

True, but i think thats just because of the nature of a while loop. They can work on conditinal alone. That works if you throw a 1 in there: while(1)...

while(1)...
//is the same as:
int i=1;
for(;;)...