printing value of char variable in C

Question

hi everyone
how can i print the value like 127 in C as a signed char or 255 as unsigned char,
as i have tried using priintf("%c",char_var) but got garbage values or a single character.
please help.
thanks in advance.

Answer 1

i am working on a sensor having 8bit value i want to use char to store and print its value,suggest me.

Answer 2

char ch = 'a' ;
pruntf("%c = %d", ch, ch);
Outout:
a = 97

Check this code for all values of charf from 1 to 255

#include <stdio.h>
int main() {
for(unsigned char c=1; c<=255;c++)
printf("%c = %d \n",c ,c);
return 0;
}

Answer 3

Jayakrishna🇮🇳 and what about inputting value in char variable like 127 ?

Answer 4

and then printing it.

Answer 5

Jayakrishna🇮🇳
thanks for your help but i got that,
as
char c;
scanf("%d",c);
printf("%hhd",c);

Answer 6

it will take input of length equal to char as integer.

Answer 7

You mean int 127 to char ch
Like
char ch;
scanf("%c", &ch);
and input 127, then it only read 1, as you taking char %c..
If you want int 127, as a charecter asci value, then
take it as int,
int ch;
scanf("%d", &ch);
Input 127,
printf("%c", ch);
127 is I think, invisible character, so try with 97, then
You output is 'a'.

Answer 8

Jayakrishna🇮🇳

check it out.

#include <stdio.h>

int main() {
char i;
scanf("%hhd",&i);
printf("%c=%hhd\n",i,i);
return 0;
}