How to return the number of elements that satisfy a specific condition within a list in Python?

Question

CONSIDER THE FOLLOWING LIST - TO FIND THE NUMBER OF ELEMENTS THAT CONTAIN CHARACTER "n"

list1 = ["Chennai","Bangalore","Delhi","25","67",100,25.2,"University"]

strlist = [str(list1) for list1 in list1] #casting the values of the list as string

for i in range(0,len(strlist)):
n=strlist[i].find("n")
if (n!= -1):
print(strlist[i])

THIS COULD PRINT THE ELEMENTS CONTAINING THE CHARACTER "n" IN THE LIST
BUT HOW DO I PRINT THE NUMBER OF ELEMENTS(THE COUNT) THAT CONTAIN CHARACTER "n" ???
[i.e. the no. of elements that contain "n" within the list = 3]

any ideas peeps!?!?!?

Answer 1

Incrementing a variable say count whenever n is found in a list item

list1 = ["Chennai","Bangalore","Delhi","25","67",100,25.2,"University"]

strlist = [str(list1) for list1 in list1] #casting the values of the list as string
count=0;
for i in range(0,len(strlist)):
n=strlist[i].find("n")
if (n!= -1):
count+=1
print(count)

Edit: another Alternative to do this as a one-liner is using list comprehension and through functional programming

print(len(list(filter(lambda x:"n" in x,list(str(i) for i in list1)))))

Answer 2

A possible solution:

list1 = ["Chennai","Bangalore","Delhi","25","67",100,25.2,"University"]
print(len([i for i in list1 if 'n' in str(i)]))

Answer 3

You can use this

for element in list1:
if n in element :
nb_element+=1
nb_n += element.count('n')

Answer 4

Thanks much! 😊😊😊
Abhay
Nathan Sikati
Mirielle
Jayakrishna🇮🇳

Answer 5

Mirielle thks for letting me know

Answer 6

list1 = [ "Chennai","Bangalore","Delhi","25","67",100,25.2, "University"]

strlist = list( filter( lambda x : 'n' in str(x), list1 ) )
# 👆 Only if true, added to list

print(strlist)
print(len(strlist))