How can we round off a float value to the nearest integer in python?

Answer 1

my recommendation:
don't use any function

use like this:
if(21%2==0):
print(21//2)
else:
print((21//2)+1)

adding 1 is best way for knowledge
if division gives float add one

Answer 2

Your last code IS the best method (that I know)

Answer 3

import math

print(math.ceil(21/2))

mc = math.ceil
print(mc(33/4))

Answer 4

Your code will round down, or round up depending on your decimals.
Your question indicates that you want all decimal results to round up.
Can you clarify exactly what you are trying to achieve

Answer 5

Let me clarify my doubt: the user inputs a positive integer which is to be divided by another positive integer. The quotient should be rounded off to the nearest integer.
Eg. 200/3=66.666...=~67

Answer 6

Here's how I solved it:
divd = int(input())
divs = int(input())
quo = divd/divs
rem = quo%1
ans = int(quo)
if rem<0.5:
print(ans)
elif rem==0.5:
if ans%2==0:
print(ans)
else:
print(ans+1)
else:
print(ans+1)

Answer 7

Found a direct method:
divd = int(input())
divs = int(input())
quo = divd/divs
print(round(quo))

Answer 8

Rik Wittkopp Edited👍 I wanted to round off