This is a code to find the reverse of a number. I understand the logic but I don't understand why it is so Someone pls explain.

Question

Reverse of a Number - JavaScript
https://code.sololearn.com/W9mrLFq098tk/?ref=app

Answer 1

What's your question?
For code advertising use your personal feed post..

Answer 2

Edewor Righteous
For example input is 1234
Then by code first iteration
no=1234;
while(no>0) {
a=no%10; //now a =1234%10=4.
no=parseInt(no/10); //no=no/10=>1234/10=123
temp=temp*10+a; //here temp=0*10 + a = 4
}
In next iteration no =123.
And a = no%10=123%10=3
no=123/10=12
temp = temp*10 + a= > 4*10 + 3= 43

In next iteartion
a=12%10=2
no=12/10=1
Temp=43*10+2=432

In next iteration :
a =1%10=1
no=1/10=0
Temp = 432*10 + 1=4321

no>0 while condition is false now so loop stops here.. It alert(temp) =4321.
Hope it clears..

Answer 3

Yes I understand now. Thank you Jayakrishna🇮🇳

Answer 4

No I'm not advertising. I don't understand the logic used in this code. I need some explanation. I'll repost. Please take a look at it again.

Answer 5

You're welcome..