Question generator text split

Question

I struggle with the pro version code exercice.
Please help me

The exercice with pro version is

**
Given a string as input, create a generator function that splits the string into separate words and outputs the resulting list.

Sample Input
This is some text

Sample Output
['This', 'is', 'some', 'text']
**

Answer 1

Igor Romasenko also,
you can print the values using for loop and generator:

def words():
str = txt.split()
yield str

getwords = words()
for w in getwords:
print(w)

Answer 2

Sob Xav
**They can be created using functions and the 'yield' statement.

[ Edited: ]
def words():
for i in txt.split():
yield i

Answer 3

Igor Romasenko the task says: split the string into separate words and output the resulting list.
txt = input()
..
print(list(words()))

[ Edited: ]
To iterate over words of a string:

• Split the string. The common delimiter between words in a string is space. The split() returns an array. Each element in the array is a word.
    str = txt.split()

• Use for loop to iterate over the words present in the array.
    for s in str:

and than use 'yield' statement:
**The 'yield' statement is used to define a generator, replacing the 'return' of a function to provide a result.
• https://code.sololearn.com/c7gIWDrcNljm/?ref=app

Answer 4

Igor Romasenko You are very welcome buddy!👍🍻🍻
I hope it was helpful.😉

Answer 5

What language you are talking about?
Before you can get help, please do a try by yourself first, store it in playground and post your attempt here. Thanks!

Answer 6

Sob Xav , is the description you gave us really the once that is used in the task description? Can you just copy and past it? Thanks!

Answer 7

txt = input()

def words(txt):
#your code goes here
lista = txt.split(' ')
for w in lista:
yield w
print(list(words(txt)))

Answer 8

txt = input()

def gen_list_str(txt):
for word in txt.split(''):
yield word

print(list(gen_list_str(txt)))

What's wrong with this code?
Someone please help me.

Answer 9

Vaishnavi Mani ,

the code uses an empty string as separator which creates an error. for default splitting at a space, we can just let the parenthesis of split() function empty. use:

for word in txt.split():

Answer 10

Sorry, it is python.

Code but it is clearly not making the job and not using a generator as requested.

I'm lost...

txt = input()

def words(x):
#your code goes here
x.split(" ")
return x

print(list(words(txt)))

Answer 11

Hi , remove that list function from the print statement ,
x.split(" ") is already returning a list with words seperated by space

Answer 12

Danijel, the problem is that the input is a string

Answer 13

Danijel Ivanović, thanks a lot!

Answer 14

Thank you all for the help 🙏🙏🙏

Answer 15

def slt(pera):
for word in pera.split():

yield word

x=input()
print(list(slt(x)))

Answer 16

txt = input()

def words(x):
#your code goes here
return x.split(" ")

print(words(txt))

The shortest version:
print(input().split(" "))

Answer 17

txt = input()

def words():
return txt.split()

print(list(words()))

Answer 18

Lothar
Thanks alot

Answer 19

Lothar, the full description is above in my first message, and the empty code is :

txt = input()

def words():
#your code goes here

I guess I will skip this one... Too weird

Answer 20

txt = input()#1. Gets input text
def words():
#your code goes here
l=txt.split(' ')#2. Store each word as a list item
for i in l:
yield i #3. yield each item one at a time to the print statement
print(list(words())) #4. Converts each yielded value to a list item and prints.