a=7; p= 0; solve: p+=(++a)-(--a); plz explain and solve

Question

answer is 0 maybe but i cant understand plz explain. java expressions question.

Answer 1

I think you have not noticed answer properly . Output should be 1 instead of 0 . I tried in c cpp and java it giving 1 not 0.

public class Program
{
public static void main(String[] args) {
int a=7,p=0;
p=p+ (++a)-(--a);
System .out.println (p);

}
}

You intilize a=7 and p =0
When u calculate expression it will calculate like this
Her me u used pre increment and pre decrement but pre increment have highest priority so first a will increase by 1so a=8 and 8 will use in whole expression but after tha (--a) here first value will be decrease so it will again be 7
So
p=p+ (++a) -(--a)
p=0+ 8 -7
p=1

Answer 2

In C & C++ this is considered as an example of sequence point issue. Order of execution is unspecified, which leads to unpredictable (and most probably undesired) output. You will see a sequence point warning if you run this code in Code Playground.

(Edit)
Java doesn't have this symptom.