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Please find error in this?

Exception in Java

8th Oct 2020, 11:15 AM
Alan
Alan - avatar
3 Réponses
+ 8
Alan It's not an exception.. readLine() method in DataInputStream is deprecated. Deprecated class or method means it is no longer important and you should not use it. You can either use Scanner class or readLine() of BufferedReader class. Here is more info 👇 https://stackoverflow.com/questions/5611387/datainputstream-deprecated-readline-method
8th Oct 2020, 12:18 PM
Minho
Minho - avatar
0
https://code.sololearn.com/cK9a8840oMU2/?ref=app
8th Oct 2020, 11:16 AM
Alan
Alan - avatar
0
import java.io.*; public class TryText { public static void main(String[] args)//throws Exception { DataInputStream in = new DataInputStream(System.in); int a=0,b=0,c=0, x=0,y=0; try { System.out.println("Enter the first number"); a=Integer.parseInt(in.readLine()); System.out.println("Enter the second number"); b=Integer.parseInt(in.readLine()); System.out.println("Enter the third number"); c=Integer.parseInt(in.readLine()); try { x=a/(b-c); //may throw exception } //handling the exception catch(ArithmeticException e) { System.out.println("Division by zero"); } y=a/(b+c); System.out.println("Y= "+y); } catch(Exception e){} } }
8th Oct 2020, 11:16 AM
Alan
Alan - avatar