Can someone explain me this code of variable arguments in function?

Question

def total(initial=5, *numbers, **keywords):
count = initial
for number in numbers:
count += number
for key in keywords:
count += keywords[key]
return
count print(total(10, 1, 2, 3, vegetables=50, fruits=100))
Output is 166

Answer 1

Here is an explanation what happens to the various parameters in the function header:

def total(initial=5, *numbers, **keywords):
...

calling the function like it is done in the sample:
print(total(10, 1, 2, 3, vegetables=50, fruits=100))

the first argument 10 will be stored in var "initial" and will overwrite the default value of 5.
"initial": 10, type int

the next n arguments (3 integers) will be stored in "numbers", which are called "args" = arguments. the number of arguments depends on the call of the function
args: (1, 2, 3), type tuple

the next n arguments (2) will be stored in "keywords", which are called "keyword args"
the number of arguments depends on the call of the function
keywords: {'vegetables': 50, 'fruits': 100}, type dictionary

Answer 2

it just adds up all the values.

https://www.geeksforgeeks.org/args-kwargs-JUMP_LINK__&&__python__&&__JUMP_LINK/

Answer 3

Slick thanks so much helped alot !
Can you name some other useful sites like geeksforgeeks which I just discovered via you?

Answer 4

tutorialspoint.com
realpython.com
w3schools.com
stackoverflow.com
docs.python.org

Answer 5

Slick thanks again will check them out soon! 😀

Answer 6

Thanks so much Lothar for giving me your time & explaining wonderfully! 😀

Answer 7

No problem at all