In the code: for(x=1; x<=5; x++) { system.out.printIn(x); } ++x and x++ has no difference in the output ... why?

Answer 1

Because the increment of x is done at the end of the block, so is blase x++ or ++x

Answer 2

for(a, b, c)
a is executed the first time the loop is run
b is checked at the start of each loop run
c is executed at the end of each loop run
which means that in this case
the first time x is set to 1
then checks that 1<=5 is true
then prints 1
if c is ++x ----> x is set to 2
if c is x++ ----> x is also set to 2
then checks 2<=5 is true prints 2
...

in this way the example above gives the same result whether you use x++ or ++x

Answer 3

When you iterate using x++ and ++x inside the for loop syntax, first the condition is tested and code is executed once for initial declaration of x which
in this case is x =1.
After one loop, then the iteration comes into picture which will have the same effect for x++ and ++x inside the for loop syntax.
If you want to see the difference between the two, do the iteration part in the System.out.println(x++); and System.out.println(++x); instead of doing it inside the for loop syntax.

Try these two:

for(x=1; x<=5;)
{ System.out.println(x++);
}

and

for(x=1; x<=5;)
{ System.out.println(++x);
}