Whats the difference between these two?

Question

If A is a superclass of B aka B extends A, then whats the difference between these two lines?

A n = new A();
and
A n = new B();

What are all the possible differences here?

Answer 1

Here is one difference:

public class Program
{
public static void main(String[] args) {

A n1 = new A();
n1.aaa();

A n2 = new B();
n2.aaa();
}
}

public class A{
public void aaa(){
System.out.println ("aaa");
}
}

public class B extends A{
@Override public void aaa(){
System.out.println ("bbb");
}
}

// Output:
// aaa
// bbb

Answer 2

So basically the difference is that if the super and subclass have the same method name, then it will prioritize in this case A n2 = new B(); the subclass method?

Answer 3

In the first case A n = new A()
U can only use propertys and methods of the Super Class. You dont have to create class B. It is useless.
In the second case A n = new B() You're able to use overriden methods or propertys.
But I also don't know so much of this. Have only this example above.

Answer 4

Yes I was referring to this thanks