Hwo can help me in java ? Lenght of even numbers

Question

public class Program {
public static void main(String[] args) {

for(int x=0; x<=10; x=x+2) {
int[] aa = new int[x];
System.out.print(aa.length + " ");
}
}
}
// I cant have a length of even numbers

Answer 1

Ohh.. so you wanna count how many even numbers are present in the array.

Edit: Modified according to your need.
Although here count actually counts how many time the loop has been executed. The array is not necessary.
https://code.sololearn.com/c16B3pn3k8dN/?ref=app
.
.
Explanation to why your code isn't giving your desired output..

for(int x=0; x<=10; x=x+2) {
int[] aa = new int[x];
System.out.print(aa.length + " ");
}

1st iteration
x = 0
int[] aa = new int[0] <- length of array 0
_______________
2nd iteration
x = 0+2
int[] aa = new int[2] <- length of array 2
_______________
3rd iteration
x = 2 +2
int[] aa = new int[4] <- length of array 4
------------------
4th iteration
x = 4 + 2
int[] aa = new int[6] <- length of array 6
------------------
5th iteration
x = 6 + 2
int[] aa = new int[8] <- length of array 8
------------------
6th iteration
x = 8+2
int[] aa = new int[10] <- length of array 10
------------------

That's how it prints 0 2 4 6 8 10 :)

Answer 2

What do you expect the output to be?

Answer 3

eli Please don't provide any code snippets that you haven't tested before. Your code snippet will result in a compile error because int[] arr doesn’t get initialized. In order to make it compile, you would have to change the second line to:
int[] arr = new int[6];

Answer 4

Thankh you Minho , but i have a question , can you do this by another version , see
I want to compile the even numbers in one array , and print array length , can you do same?

Answer 5

Expected result must be 6 ; because the even numbers are 0,2,4,6,8,10, length of this numbers are 6

Answer 6

int i=0;
int arr[]=new int [10];
for(int x=0; x<=10; x+=2, i++){
arr[i]=x;
}

//print i or length of arr
I think it would be working but i not check this:)