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How is the last minimum number of a sequence from a file without using an array?

I have a file "input.txt" In which there are integers. I need to determine the last minimum number.

14th Nov 2020, 6:24 PM
Majid Isaev
Majid Isaev - avatar
1 Réponse
0
There is no need to use array. You will need only 2 variables which will store the number you read and a minimum. $ cat input.txt 1 42 56 9 -2 13 -18 20 33 55 -8 43 1 2 ./a.out Last minimum number is -18 $cat lastMin.c // I have a file "input.txt" In which there are integers. // I need to determine the last minimum number. #include <stdio.h> #include <stdlib.h> int main() { // create a pointer to a file FILE *pFile; // create two variables int number = 0; int min = 0; // open file pFile = fopen("input.txt", "r"); // check if the file successfully opened if (NULL == pFile ) { printf("Could not open file!"); return 1; } // EOF is a pointer for file ending // fscanf read from file an integer into a variable `number` while (fscanf(pFile, "%d", &number) != EOF) { // if the current number is less than min, we found a minimum if (number < min) { min = number; } } // print last minimum we got after reading file printf("Last minimum number is %d\n", min); // after we finished work with file we have to close file. fclose(pFile); return 0 ; }
7th Feb 2023, 7:06 PM
Oleksandr Gorlinskyi
Oleksandr  Gorlinskyi - avatar