JS sort one array based on another array’s sortation

Question

arrA = [8, 6, 7] // B follows this arr (A)
arrB = [‘h’, ‘u’, ‘z’] // B follows A

arrA.sort()
// output: 6, 7, 8

// arrB.followA’s arrangement somehow
// output: u, z, h

arrA.reverse()
// output: 8, 7, 6

// arrB.follow A’s arrangement
// output: h, z, u

Code that I started:
https://code.sololearn.com/WVQeIKjN26SE/?ref=app

Answer 1

Let combinedArr = arrA.map((el,i)=> [el, arrB[i]])
Then sort based on the first item of the sub arrays of the variable "combinedArr" (sort() accept a call back function)
then separate them using filter (number or letters?) Into two new variables (or the same old variables a and b if you want) and you are done

Answer 2

Feel free to ask for clarification

Answer 3

var arrA = [6, 8, 7];
var arrB = ['h', 'u', 'z']

let combinedArr = arrA.map((el,i)=> [el, arrB[i]])

console.log(combinedArr);

combinedArr.sort((a,b)=> a[0] - b[0]); // sorting based on the number
arrA = combinedArr.flat().filter(el=> typeof el == "number");
arrB = combinedArr.flat().filter(el=> typeof el == "string")

console.log(arrA , arrB )

Answer 4

Ali Kh is it aight if u walk me through..

I got this so far, don’t understand what’s next. (even though u said it in ur comment above)
https://code.sololearn.com/WV5RWyr0O40r/?ref=app