Smallest element in array java

Question

I have typed the code to find the smallest element in the array

but I have a question

The smallest value in the array is 1 and I write a condition using the conditional f statement it says
If the first element in the array is less than the smallest element then fulfill the following condition

However, the smallest element in the matrix is 1 and the first element in the matrix is also 1

And 1 is not less than 1, but fulfills the condition

How can this be ? Please explain to me a detailed explanation

https://code.sololearn.com/cP84GC4jrQ0Q

Answer 1

public class Program
{
public static void main(String[] args) {
double [] myList= {1,5,4};
double min=myList[0];
int indexOfMin =0;
for(int i=0;i<myList.length;i++)
if(myList[i]<min) {
min=myList[i];
indexOfMin =i;}
System.out.print(myList[indexOfMin]);
}
}
Variable indexOfMin is assigned to 0, even if the condition failed variable value is still 0.
That's why it's returns the first element of the array Even your condition gets false.

Answer 2

STOP I don't see any problem with your code, works fine. Don't need any edits in your code.

Answer 3

STOP if condition failed than no new value will be assigned to the variable indexOfMin.
Variable value is unchanged and remains as you assign it while declaration.

and program prints is somewhat similar to myList[0](first one of array).

Answer 4

what do you mean of

even if the condition failed variable value is still 0. ?

0_O-[Mägár_Sám_Äkà_Nüllpøïntêr_Èxëcéptïön]~~

Answer 5

0_O-[Mägár_Sám_Äkà_Nüllpøïntêr_Èxëcéptïön]~~

can you more explain, and if there any edit to make the code better help me

Answer 6

I can’t understand:((((

Answer 7

// 0 1 2
double [] myList= {1,5,4};
// 1
double min=myList[0];

for(int i=0;i<myList.length;i++)

if(myList[i]<min) {
min=myList[i];
min =i;}
System.out.print(min);

}

}

I delet indexOfMin. and still gibe me 1
hhhoooowwww

Answer 8

STOP your if statement is never executed. The indexOfMin was assigned 0 so even at the end only that is printed so myList[indexOfMin] is myList[0] which is 1.

Answer 9

Avinesh

// 0 1 2
double [] myList= {1,5,4};
// 1
double min=myList[0];

for(int i=0;i<myList.length;i++)

if(myList[i]<min) {
min=myList[i];
min =i;}
System.out.print(min);

}

}

I delet indexOfMin. and still give me 1
hhhoooowwww

Answer 10

STOP because you already assigned min = myList[0] and printing min will give 1.

Answer 11

ooookkaaaayyy