Whats the problem with sizeof()??

Question

When i define an array and want to find the length of that by sizeof() , it doesn't work properly ,
int a[3]={1,3,4};
int b = sizeof(a);
cout<<b;
The output must be 3 , while it shows 12 . What's the problem ?? Although I do know that there's an alternative I mean *(&a+1)-a , which works so well.

Answer 1

A int in this case is 4 bytes and 4*3=12.

Answer 2

Ali_combination the array has 3 ints. The size of 1 int is 4 bytes and therefore the size of array of 3 ints is 4*3 = 12 bytes

Answer 3

to get the size of the array , you should be doing
sizeof(a)/sizeof(int)

Answer 4

You are all right ! 👍 Thank you so much gentlemen.

Answer 5

Aaron Eberhardt You are right , thanks a lot. I apologize for downvoting your comment.

Answer 6

Ali_combination no need to apologize :)

Answer 7

Nope , take a look at this
a=[3]={1,2,3}
int b = sizeof(a);
Cout<<b;
The outputs is 12.