Ascending order of 3 numbers without array

Question

Hello everyone, I've recently started to learn programming in C++, recently as in exactly 8 days so far.
For my problem, I am given 3 random numbers that don't have to be unique and I have to ascend them in order from lowest to higher ( i forgot to mention the part that english is not my first language and if I didn't explain something right pls let me know)
here's what I've tried so far :
#include <iostream>
using namespace std;

int main() {
int a=3, b= -1, c=20;
cin>>a>>b>>c;
if (a<=b) {
cout << a << " " << b <<" "<< c;
}
else if (b<=c) {
cout << b << " " << a <<" " << c ;

}

return 0;
}

as you can tell this is not right, well, its right for some numbers but not for all the numbers.
on the cout it has to show only 3 number in ascending order and nothing else, for some numbers it will show like 10 digits and thats because I don't know yet how to stop that and only show in consol what i need. this is becoming way too long so I'l cut it off
What am i doing wrong, what else can I try and what am I missing here?
I can use also the && symbol besides this and the symbols shown above I cant use something else.
p.s I dont want someone to type the whole code as it will not help me in any way.

Answer 1

Use the min and max function...remember you can nest them, and a little bit of maths to output the middle value.
You might have to #include algorithm header, although.. I have see it work without it.....(might be included in iostream.).

Answer 2

i can't use that function.
i can only use " if, else if, &&, <, <= and thats about all i can use