Snail in the well

Question

Got the first two visible case couldnt solve the hidden cases

My attempt
https://code.sololearn.com/W6w4Iu3P2iLE/?ref=app

Answer 1

elvisreal , in fact you don't need to perform so complex calculations using slice, split, reverse and Math.floor method. Just follow the description. Don't just add 5 each day, because you should make a check if the length >= depth after increasing the length with 7. Look at the corrected code. Hope it helps you.
https://code.sololearn.com/Wk4uxTS9bHaB/?ref=app

Answer 2

It's very simple

TRY THIS 👇🏻

let day = 1;
for(let height = 7; height < depth; height += 5 ){
day++;
}
console.log(day)

🥳🥳🥳🥳

Answer 3

I solved this about 3 hours
So don’t just copy and paste the code next time, try also your best

function main() {
var depth = parseInt(readLine(), 10);
var days = 0; seven = 7; two = 2; total = 0; isDone = false;

while(!isDone){
total += seven;

if(total >= depth){
isDone = true;
} else{

total -= two;
}

days++;

}

console.log(days);
}

Answer 4

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
day=0
for (;depth>0;day++){
depth-=7
if(depth>0){
depth+=2
}
}
console.log(day)
}

Answer 5

//the best solution
function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var
go = 7-2
var dist = 0
var day = 0
for(let go =5; dist<=depth-3; dist +=go){
day+=1

}
console.log(day)
}

Answer 6

https://code.sololearn.com/WNrSUM96dDqt/?ref=app

Answer 7

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var d=0;
var i=0;
for(i=0;d<depth;i++)
{
d=d+7;/*during day(d) it covers 7 feet*/
if(d>=depth)/*the loop will break when it climbs the whole depth*/
{
i=i+1;/* here,i= no.of days*/
break;
}
d=d-2;/*it slips down 2 feet at night*/
}
console.log(i);
}

Answer 8

function main() {
var depth = parseInt(readLine(), 10);
//tu código va aquí
var d = 0; // días
var c = 0; // caracol
while (c < depth) {
c += 7 - 2;
d += 1;
if (c > depth) {
if (c - 2 <= depth) {
console.log(d);
break;
}
else if (c > depth) {
console.log(d - 1);
break;
}
}
}
}

Answer 9

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var i=0;
var day=0;
while(i<depth){
day+=1;
i+=7;
//if the snail is already at the top by day it doesnt need to slip anymore at night
if(i<depth){
i-=2;
}else{
break;
}
}
console.log(day);
}

Answer 10

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
console.log(Math.ceil((depth-2)/5));

}

Answer 11

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var day = 0;
var num = 0;
if (depth>0)
{
do{
num += 7;
if (num==depth){
continue;
}
else if(num<depth)
{
num-=2;
}
day++;
}while (num<=depth);
}
console.log(day);
}

Answer 12

console.log(Math.round(depth/5))

most efficient method

Answer 13

for(w=5; w <= w; w+=5){
var work=w;
console.log(Math.round(depth/work))
{break;}

}
}

The Math.round() function returns the value of a number rounded to the nearest integer.
is if 48 dethp/w = 8.4 eith math .round its 8

Answer 14

In fact you don't even need a loop. You can get the answer with a single line of arithmetic operations.

Hint: there is a linear relation between input and output

Answer 15

https://www.sololearn.com/Discuss/2612727/?ref=app

Answer 16

Jesse Franco Latosa thanks but i solved it my own way nice code tho

Answer 17

function main() {
var x = parseInt(readLine(), 10);
var y = 1;

for (;;y++) {
if ((y*5)>=(x-2)) {
break;}
}
console.log(y);
}

Answer 18

@Jesse Franco Latosa
could you please explain the code?

Answer 19

function main() {
var depth = parseInt(readLine(), 10);
for(i=0;depth; i+7-5);

}

Answer 20

function main() {
var depth = parseInt(readLine(), 10);
//your code goes var
//D is distance travel each day
var day=0;
for(D=0; D<depth; day++)
{ D+=7;
if(D>=depth){
day++
break;
}
D-=2;
}
console.log(day)
}