Palindrome numbers

Question

#include <iostream>
using namespace std;

bool isPalindrome(int x) {
//complete the function

}

int main() {
int n;
cin >>n;

if(isPalindrome(n)) {
cout <<n<<" is a palindrome";
}
else {
cout << n<<" is NOT a palindrome";
}
return 0;
}

Answer 1

My answer plus an explanation on how this works since that's what's important:

#include <iostream>
using namespace std;

bool isPalindrome(int x) {
//complete the function
int num, rem, rev=0;

num=x; //to be able to save new values to compare original with
while(x != 0)//to end loop once x=0
{
rem = x%10; //1st step divides number by 10 and makes the remainder the value of rem. Ex. 1234/10=123.4 rem=4
rev= rev*10 + rem; //reverse number starts at 0 *10 + rem(4)=4
x /= 10; //x becomes the value of x/10(123)
//these steps repeat. Rem=3, rev =4*10+3=43, x=123/10=12, until rev= 4321 and x=0.

}

if (rev==num)
{
return true;
}
else
{
return false;

}

}
int main()
{

int n;
cin >>n;

if(isPalindrome(n)) {
cout <<n<<" is a palindrome";
}
else {
cout << n<<" is NOT a palindrome";
}

return 0;
}

Answer 2

#include <iostream>
using namespace std;
int main()
{
int n,r,sum=0,temp;
cin>>n;
cout <<n;
temp=n;
while(n>0)
{
r=n%10;
sum=(sum*10)+r;
n=n/10;
}
if(temp==sum)
cout<<" is a palindrome";
else
cout<<" is NOT a palindrome";
return 0;
}
Thats the only thing you are looking for

Answer 3

John Christian Lopez

Return true if previous value and new value is equal otherwise return false.

Answer 4

bool isPalindrome(int x) {
//complete the function
int n, rev = 0, rem;
n = x;
while (n > 0) {
rem = n%10;
rev = rev*10 + rem;
n /= 10;
}
return rev == x;
}

Answer 5

//with bool function

#include <iostream>
using namespace std;

bool isPalindrome(int x, int y) {
if(x==y){
return true ;
}
else{
return false ;
}

}
int reverse(int z){
int r=0;
while(z!=0){
r=r*10;
r=r+z%10;
z=z/10;
}
return r;
}

int main() {
int n;
cin >>n;
int j =reverse(n);

if(isPalindrome(n,j)) {
cout <<n<<" is a palindrome";
}
else {
cout << n<<" is NOT a palindrome";
}
return 0;
}

Answer 6

#include <iostream>
#include <string.h>
#include <stdlib.h>
#include <cmath>

using namespace std;

void verNumber(int arr[], int len, int num){

for (int i = 0; i < len ; i++)
{
cout <<i<<" "<<arr[i]<<endl;
}

if((arr[0] == arr[len-1]) && (arr[1] == arr[len-2]))
{
cout<<num<<" is a palindrome"<<endl;

}else
{
cout<<num<<" is NOT a palindrome"<<endl;
}

}

void isPalindome(int num, int len){

int arrNum[len];
for (int i = 0; i < len ; i++)
{
arrNum[i] = (int) floor(num/pow(10,(len-(i+1)))) % 10;

}

verNumber(arrNum,len,num);

}

int main(){

char data[5];
cin>>data;

int len = strlen(data);
int num = atoi(data);

isPalindome(num,len);

return 0;
}

Answer 7

short and good!

#include <iostream>
using namespace std;
int main(){int n,r,sum=0,temp;
cin>>n;
cout <<n;
temp=n;
while(n>0)
{r=n%10;
sum=(sum*10)+r;
n=n/10;}
if(temp==sum)
cout<<" is a palindrome";
else cout<<" is NOT a palindrome";
return 0;}

Answer 8

int n=84648 r, sum=0, temp; // for example n is = 84648
cout <<n;
temp=n; // 84648

while(n>0)
{ //loop until n =0: first 2th 3th 4th 5th
r=n%10; // 8 4 6 4 8
sum=(sum*10)+r; // 8 84 846 8464 84648 now is sum = 84648
n=n/10; // 8464,8 846,48 84,648 8,4648 0,84648 n is int therefore doesn't include after comer ,84648
}

Answer 9

hmmm. looks like that code is wrong. maybe you pasted something else?
hint looks like it takes in parameter x and overwrites it with n.
also does not look like isPalindrome returns true or false (missing return statement).

Additional, things to consider, maybe this could help you:
—
Are there other things that could be palindromes? other than numbers?
are you going to rewrite this if you get asked to instead check if a string is a palindrome?
would checking if a sting is a palindrome be easier than a number?

Answer 10

i am also on this problem and this answer that is provided does not work... i am glad it didnt work because i want to understand how it works and why they provided a global bool function. and then call the function in an if statement, ( i am guessing (n) is now == to x or the fucntion parameter.)
im not sure what is going on here and i need help understnding what is going on so we can answer this problem correctly. ... why did they use a global bool function????

Answer 11

Umm hi guys, How are you all

Answer 12

bool isPalindrome(int x) {
int length = to_string(x).length() -1;
string xxx;
for (length; length != -1; length--){
xxx = xxx + to_string(x)[length] ;
}
if (xxx == to_string(x)) { return true; } else{ return false; }
}
you have to #include<string>
:)

Answer 13

Visit here for better & easy solution :-

https://code.sololearn.com/c0a209a25a0A

Answer 14

#include <iostream>
using namespace std;
int main()
{
int n,r,sum=0,temp;
cin>>n;
cout <<n;
temp=n;
while(n>0)
{
r=n%10;
sum=(sum*10)+r;
n=n/10;
}
if(temp==sum)
cout<<" is a palindrome";
else
cout<<" is NOT a palindrome";
return 0;
}

now it's working

Answer 15

use % module to reverse the whole number one by one and you could use a while loop to make it easy

#include <iostream>
using namespace std;

bool isPalindrome(int x) {

//complete the function

int neww, div, rem, rem1;

// first part out of the loop

rem1 = x % 10; // get the first number of the reversed x
div = x / 10; // substract the last number of x
neww = rem1; // begin the neww reverse number

// reverse the whole number

while ( div > 10 ) {
rem = div % 10;
neww = neww*10 + rem;
div = div / 10;
}
neww = neww*10 + div; /* concatenate the first number of x as
as the last one in the reverse*/
if ( x == neww) {
return true;
} else {
return false;
}

}

int main() {
int n;
cin >>n;

if(isPalindrome(n)) {
cout <<n<<" is a palindrome";
}
else {
cout << n<<" is NOT a palindrome";
}
return 0;
}

Answer 16

#include <iostream>
using namespace std;

bool isPalindrome(int reverse, int check) {
//complete the function
bool status = true;
if (reverse != check) {
status = false;
}
return status;
}

int main() {
int n, reverse = 0, rem;
cin >> n;
int check = n;

while(n != 0){
rem = n % 10;
reverse = reverse * 10 + rem;
n /= 10;
}

if(isPalindrome(reverse, check) == 1) {
cout << reverse <<" is a palindrome";
} else {
cout << check <<" is NOT a palindrome";
}
return 0;
}

Answer 17

Why the reason we used so much 10 ?? All answers so similar.

Answer 18

#include <iostream>
using namespace std;
#include <string>

void rev(string num,int len,int save){
string cache;
for (int x = 1; x < len+1; x++){
cache+=num[len-x];
}
cout << save;
if ( to_string(save) == cache ){
cout << " is a palindrome";
}
else{
cout << " is NOT a palindrome";
}
}
int main(){
string num;
cin >> num;
rev(num,num.length(),stoi(num));
return 0;
}

Answer 19

Explanation in the comments:
https://code.sololearn.com/c1qOCghBDq6m/?ref=app