Having trouble returning x

Question

I wrote this code to take input, and then check each character of the string and add numers together dependant upon which letter it reads:

W = input("Enter a Word: ")
print (W)
r = 0
for i in W:
r += 1
print (r)

This is how I take the word from the user and find the length of the word.

This next bit of code is a little wet but its supposed to check each letter in the string, and depending on that letter; a number is added to x:

w1 =[W]
i = 0
x = 0
while i < r:
if (w1 [0][i]) == 'A' or 'a' or 'J' or 'j' or 'S' or 's':
i += 1
x += 1
elif (w1 [0][i]) == 'B' or 'b' or 'K' or 'k' or 'T' or 't':
i += 1
x += 2
elif (w1 [0][i]) == 'C' or 'c' or 'L' or 'l' or 'U' or 'u':
i += 1
x += 3

Print (x)

Let's say "ABC" is input. It should add 1 to x for a, +2 for b and ×3 for c making x = 6. However when I try it, it will only give 3 or however many letters are in the input. Can anyone tell me why or how to adjust this so it gives me 6 as intended?

Answer 1

There no need for the first loop, python has a function called len() that returns the length of the string....and..in your second while loop, your trying to access the individual character as though it was a 2 dimensional array, which it isn't..so.....this is how I would do what your trying to do...

W = input("Enter a Word: ")
x = 0
for c in W:
if c.lower() in ['a', 'j', 's']:
x += 1
elif c.lower() in ['b', 'k', 't']:
x += 2
elif c.lower() in ['c', 'l', 'u']:
x += 3
print(x)

or...

mydict = {'a': 1, 'j': 1, 's': 1, 'b': 2, 'k': 2, 't': 2, 'c': 3, 'l': 3, 'u': 3}
z = 0
for c in W:
z += mydict.get(c.lower(), 0)
print(z)

Answer 2

I'm sorry, +3 not × ^^