Given a list of birth years calculate how old these people will be in the year 2050 and, output the resulting list.

Question

I m not a pro member so i am unable to open it.
but i want to understand these type of code coach problems.can anyone help me to understand this?

Answer 1

It's not possible, you have to take Pro for unlocking all lessons and code-coaches, but if you wanna know these questions you can talk with a pro member. But I think it's not fair.

Answer 2

If you wish to understand it, then write your own concept and test the results against values you can manually calculate.
This will give you a much deeper understanding, & teach you how to develop code without relying on others to validate

Answer 3

birth_years = [1995, 2004, 2019, 1988, 1977, 1902] #1. All birth years stored in this list
result=list(map(lambda x: 2050-x,birth_years))#2. Ages calculated and stored in this list using map and lambda
print(result) #3. Print the age list

Answer 4

def future_age(x):
return 2050 - x
birth_years = [1995, 2004, 2019, 1988, 1977, 1902]
result = list(map(lambda x: 2050 -x, birth_years))
print(result)

Answer 5

birth_years = [1995, 2004, 2019, 1988, 1977, 1902]

#your code goes here
b=list(map(lambda x: -x+2050,birth_years))
print(b)

Answer 6

birth_years = [1995, 2004, 2019, 1988, 1977, 1902]

#your code goes here
result = list(map(lambda x: 2050-x, birth_years))
print(result)

Answer 7

Ill help you understand it.
Stop being cheap and buy the pro membership

Answer 8

Think this is shortest code:

result = list(map(lambda x: (x-2050)*-1, birth_years))
print(result)

Ask if u have questions!