Exact word in a sentence: JavaScript

Question

includes() also checks of substring of a word but I want to find only exact full word is present or not.

https://code.sololearn.com/WnrPuIHE7REP/?ref=app

Answer 1

harshit check here
https://code.sololearn.com/W8J4AJWDQ3Lu/?ref=app

Answer 2

first split all the words into an array

const words = "Full Word".split(" ")
// this will split the phrase from where ever it finds " ", i.e. a space. So now, words is equal to [ "Full", "Word" ]

let found = false
// use appropriate variable names, such as found.

// 'includes' also works on arrays, and it doesn't match the substrings when used with array.
if (words.includes("Fu")) found = true

document.getElementById("demo").innerHTML = found

Answer 3

You can split your sentence into array.

var array = entry.split(" ");

Then loop over the array to find the exact word. 🚀

Answer 4

Zohaib 👑 any simple example ?

Answer 5

var n = str.split(' ').includes("Fu");